# A 1.5kg mass is moving in a circular motion with a radius 0.8m. If the stone moves with a constant speed of 4.0m/s, what is the maximum and minimum tension on the string?

## Answer

The centripetal force on the stone is provided by the tension in the string.

Its magnitude is F = mv^2/r

Where m is the mass = 1.5 kg

v is the linear velocity of the stone = 4.0 m/s

and r is the radius of curvature = 0.8 m

So F = (1.5)(4.0^2)/0.8 = 19.2 N

Updated on March 16, 2018

### Original Article:

By Eugene Brennan