Updated date:

Mar 25, 2020

Calculator Techniques for Quadrilaterals in Plane Geometry

Author:

Ray is a licensed engineer in the Philippines. He loves to write about mathematics and civil engineering.

What Is a Quadrilateral?

A quadrilateral also called as "Tetragon" or "Quadrangle", is a general term for any polygon with four sides. There are six types of quadrilaterals. They are square, rectangle, parallelogram, trapezoid, rhombus, ad trapezium.

Common Parts of a Quadrilateral

The common parts of a quadrilateral are described as follows.

1. Side - A side is a line segment which joins any two adjacent vertices.

2. Interior Angle - An interior angle is the angle formed between two adjacent sides.

3. Height or Altitude - It is the distance between two parallel sides of a quadrilateral

4. Base - This is the side that is parallel to the altitude.

5. Diagonal - This is the line segment joining any two non-adjacent vertices

Calculator Techniques for Quadrilaterals in Plane Geometry
John Ray Cuevas


Quadrilateral	Description	Area	Perimeter
Square	A special type of a rectangle in which all the sides are equal.	A = a^2	P = 4a
Rectangle	A parallelogram in which the interior angles are all right angles.	A = ab	P = 2b + 2a
Rhombus	A parallelogram in which all sides are equal.	A = (1/2) (d1) (d2)	P = 4a
Trapezoid	A quadrilateral with one pair of parallel sides.	A = (1/2) (a + b) (h)	P = a + b + c + d
Trapezium	A quadrilateral with no parallel sides.		P = a + b + c + d
Parallelogram	A quadrilateral in which the opposite sides are parallel.	A = bh OR A = absin(theta)	P= 2a + 2b

Properties of a Parallelogram

1. The opposite sides of a parallelogram are equal, and so also the opposite angles.

2. The diagonals of a parallelogram bisect each other.

3. If two sides of a quadrilateral are equal and parallel, then the other two sides are equal and parallel, and the figure is therefore a parallelogram.

Cyclic Quadrilateral

A cyclic quadrilateral is a quadrilateral whose vertices lie on the circumference of a circle. According to Ptolemy's theorem, the product of the diagonals of any cyclic quadrilateral is equal to the sum of the products of the opposite sides.

d₁d₂ = (a) (c) + (b) (d)

Problem 1: Area of a Rhombus

A rhombus has diagonals of 32 and 20 inches. What is the area?

Calculator Technique

a. Given the length of the rhombus' diagonals, use the formula in solving for the area.

d1 = 32 inches
d2 = 20 inches
Area of rhombus = 1/2 (d1) (d2)
Area of rhombus = 1/2 (32) (20)
Area of rhombus = 320 square inches

Final Answer: The area of the rhombus is 320 square inches.

Problem 2: Square Inscribed in a Semicircle

Find the difference of the area of the square inscribed in a semicircle having a radius of 15 centimeters.

Calculator Technique

a. Calculate the side length of the square inside the semicircle.

a^2 + b^2 = c^2
x^2 + (x/2)^2 = 15^2
x^2 + (x^2/4) = 225
5/4 x^2 = 225
x = 180 centimeters
x = 13.42 centimeters

b. Solve for the area of the semicircle.

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Area of semicircle = (pi) (r)^2 / 2
Area of semicircle = (pi) (15)^2 / 2
Area of semicircle = 353.49 square centimeters

c. Solve for the area of the square inscribed.

Area of square = x^2
Area of square = (13.42)^2
Area of square = 180.10 square centimeters

d. Get the difference of areas.

Area difference = Area of semicircle - Area of square
Area difference = 353.49 - 180.10
Area difference = 173.39 square centimeters

Final Answer: The difference of the area of the square inscribed in a semicircle is 173.39 square centimeters.

Problem 3: Lengths of Trapezoid's Bases

A trapezoid has an area of 36 square centimeters and a height of 2 centimeters. Its two bases have a ratio of 4: 5. What are the lengths?

Calculator Technique

a. Solve for the area of the trapezoid.

Altitude of trapezoid (h) = 2 centimeters
Area of trapezoid = 36 square centimeters
Area of trapezoid = (1/2) (b1 + b2) (h)
36 square centimeters = (1/2) (b1 + b2) (2)

b. Let b₁ = 4x and b₂ = 5x. Solve for the value of x.

36 square centimeters = (1/2) (b1 + b2) (2)
36 square centimeters = (1/2) (4x + 5x) (2)
36 square centimeters = 4x + 5x
36 square centimeters = 9x
x = 4 centimeters

c. Solve for b₁ and b₂ by substituting the value of x.

4x = 4 (4)
4x = 16 centimeters
5x = 5 (4)
5x = 20 centimeters

Final Answer: The lengths of the trapezoid's bases are 16 and 20 centimeters.

Problem 4: Diagonals and Angles of a Rhombus

One of the diagonals of the rhombus is 12 inches. If the area of the rhombus is 132 square inches, determine the following.

a. length of the other diagonal
b. the measure of acute angles in degrees between the two sides

Calculator Technique

a. Solve for the length of other diagonal using the formula for area.

Area of rhombus = 1/2 (d1) (d2)
132 square inches = 1/2 (12 inches) (d2)
d2 = 22 inches

b. Solve for the length of one side of the rhombus using the Pythagorean theorem.

X^2 = 11^2 + 6^2
X = 12.53 inches

c. Solve for the angle θ.

tan θ = opposite / adjacent
tan θ = 6/11
θ = 28.61 degrees

Final Answer: The length of the other diagonal is 22 inches, and the angle between the two sides is 28.61 degrees.

Problem 5: Interior Angles of Parallelogram

Two sides of parallelogram measure 68 centimeters and 83 centimeters and its shorter diagonal is 42 centimeters. Calculate the hugest interior angle.

Calculator Technique

a. Using the cosine law, solve for the θ between the two known sides.

42^2 = 68^2 + 83^2 – 2(68)(83) cosine (θ)
θ = 30.27 degrees

b. Solve for the supplementary angle of θ.

Largest interior angle = 180 – 30.27 degrees
Largest interior angle = 149.73 degrees

Final Answer: The interior angle of the rhombus with the highest value is 149.73 degrees.

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