# Parabola Equations and Graphs, Directrix and Focus and How to Find Roots of Quadratic Equations

## The Parabola, a Mathematical Function

In this tutorial, you'll learn about a mathematical function called the parabola. We'll cover the definition of the parabola first and how it relates to the solid shape called the cone. Next, we'll explore different ways in which the equation of a parabola can be expressed. Also covered will be how to work out the maxima and minima of a parabola and how to find the intersection with the x and y axes. Finally, we'll discover what a quadratic equation is and how you can solve it.

## Definition of a Parabola

"A *locus* is a curve or other figure formed by all the points satisfying a particular equation."

One way we can define a parabola is that it is the locus of points that are equidistant from both a line called the *directrix* and a point called the *focus. *So each point P on the parabola is the same distance from the focus as it is from the directrix, as you can see in the animation below.

We also notice that when x is 0, the distance from P to the focus equals the distance from the vertex to the directrix. So the focus and directrix are equidistant from the vertex.

## A Parabola Is a Conic Section

**Another way of defining a parabola**

When a plane intersects a cone, we get different shapes or *conic sections* where the plane intersects the outer surface of the cone. If the plane is parallel to the bottom of the cone, we just get a circle. As the angle A in the animation below changes, it eventually becomes equal to B, and the conic section is a parabola.

## Equations of Parabolas

There are several ways we can express the equation of a parabola:

- As a quadratic function
- Vertex form
- Focus form

We'll explore these later, but first, let's look at the simplest parabola.

## The Simplest Parabola y = x²

^{The simplest parabola with the vertex at the origin, point (0,0) on the graph, has the equation y = x². }

^{The value of y is simply the value of x multiplied by itself.}

x | y = x² |
---|---|

1 | 1 |

2 | 4 |

3 | 9 |

4 | 16 |

5 | 25 |

## Let's Give x a Coefficient!

The simplest parabola is y = x^{2}, but if we give x a coefficient, we can generate an infinite number of parabolas with different "widths" depending on the value of the coefficient ɑ.

So let's make y = ɑx^{2}

In the graph below, ɑ has various values. Notice that when ɑ is negative, the parabola is "upside down". We'll discover more about this later. Remember the y = ɑx^{2} form of the equation of a parabola is when its vertex is at the origin.

Making ɑ smaller results in a "wider" parabola. If we make ɑ bigger, the parabola gets narrower.

## Turning the Simplest Parabola on Its Side

If we turn the parabola y = x^{2} on its side, we get a new function y^{2} = x or x = y^{2}. This just means we can think of y as being the independent variable, and squaring it gives us the corresponding value for x.

So:

When y = 2, x = y^{2} = 4

when y = 3, x = y^{2} = 9

when y = 4, x = y^{2} = 16

and so on...

Just like the case of the vertical parabola, we can again add a coefficient to y^{2.}

So we have x = ɑy

^{2}

## Vertex Form of a Parabola Parallel to Y Axis

One way we can express the equation of a parabola is in terms of the coordinates of the vertex. The equation depends on whether the axis of the parabola is parallel to the x or y axis, but in both cases, the vertex is located at the coordinates (h,k). In the equations, ɑ is a coefficient and can have any value.

**When the axis is parallel to y-axis:**

y = ɑ(x - h)^{2} + k

if ɑ = 1 and (h,k) is the origin (0,0), we get the simple parabola we saw at the start of the tutorial:

y = 1(x - 0)^{2} + 0 = x^{2}

**When the axis is parallel to the x axis:**

x = ɑ(y - h)^{2} + k

Notice that this doesn't give us any information about the location of the focus or directrix.

## Equation of a Parabola in Terms of the Coordinates of the Focus

Another way of expressing the equation of a parabola is in terms of the coordinates of the vertex (h,k) and the focus.

We saw that:

y = ɑ(x - h)^{2} + k

Using Pythagoras's Theorem, we can prove that the coefficient ɑ = 1/4p, where p is the distance from the focus to the vertex.

**When the axis of symmetry is parallel to y-axis:**

Substituting for ɑ = 1/4p gives us:

y = ɑ(x - h)^{2} + k = 1/(4p)(x - h)^{2} + k

Multiply both sides of the equation by 4p:

4py = (x - h)^{2} + 4pk

Rearrange:

4p(y - k) = (x - h)^{2}

or

(x - h)^{2} = 4p(y - k)

Similarly:

**When the axis of symmetry is parallel to x-axis:**

A similar derivation gives us:

(y - k)^{2} = 4p(x - h)

**Example: **

Find the focus for the simplest parabola y = x^{2}

**Answer:**

Since the parabola is parallel to the y axis, we use the equation we learned about above:

(x - h)^{2} = 4p(y - k)

First, find the vertex, the point where the parabola intersects the y-axis (for this simple parabola, we know the vertex occurs at x = 0)

So set x = 0, giving y = x^{2} = 0^{2 }= 0

and therefore, the vertex occurs at (0,0)

But the vertex is (h,k), therefore h = 0 and k = 0

Substituting for the values of h and k, the equation (x - h)^{2} = 4p(y - k) simplifies to

(x - 0)^{2} = 4p(y - 0)

giving us

x^{2} = 4py

Now compare this to our original equation for the parabola y = x^{2}

We can rewrite this as x^{2} = y, but the coefficient of y is 1, so 4p must equal 1 and p = 1/4.

From the graph above, we know the coordinates of the focus are (h, k + p), so substituting the values we worked out for h, k and p gives us the coordinates of the vertex as

(0, 0 + 1/4) or (0, 1/4)

## A Quadratic Function is a Parabola

Consider the function y = ɑx^{2} + bx + c

This is called a *quadratic function* because of the square on the x variable.

This is another way we can express the equation of a parabola.

## How to Determine Which Direction a Parabola Opens

Irrespective of which form of the equation is used to describe a parabola, the coefficient of x^{2} determines whether a parabola will "open up" or "open down". Open up means that the parabola will have a minimum and the value of y will increase on both sides of the minimum. Open down means it will have a maximum, and the value of y decreases on both sides of the max.

- If ɑ is positive, the parabola will open up
- If ɑ is negative, the parabola will open down

## How to Find the Vertex of a Parabola

From simple calculus we can deduce that the max or min value of a parabola occurs at x = -b/2ɑ

Substitute for x into the equation y = ɑx^{2} + bx + c to get the corresponding y value

So y = ɑx^{2} + bx + c

= ɑ(-b/2ɑ)^{2} + b(-b/2ɑ) + c

= ɑ(b^{2}/4ɑ^{2}) - b^{2}/2ɑ + c

Collecting up the b^{2} terms and rearranging

= b^{2} (1/4ɑ - 1/2ɑ) + c

= - b^{2}/4ɑ + c

= c -b^{2}/4a

So finally, the max or min occurs at the point (-b/2ɑ, c -b^{2}/4ɑ)

**Example: **

**Find the vertex of the equation y = 5x ^{2} - 10x + 7**

- The coefficient a is positive, so the parabola opens up, and the vertex is a minimum
- ɑ = 5, b = -10 and c = 7, so the x value of the minimum occurs at x = -b/2ɑ = - (-10)/(2(5)) = 1
- The y value of the min occurs at c - b
^{2}/4a. Substituting for a, b and c gives us y = 7 - (-10)^{2 }/ (4(5)) = 7 - 100/20 = 7 - 5 = 2

So the vertex occurs at (1,2)

## How to Find the X-Intercepts of a Parabola

A quadratic function y = ɑx^{2} + bx + c is the equation of a parabola.

If we set the quadratic function to zero, we get a *quadratic equation*

i.e. ɑx^{2} + bx + c = 0 *.*

Graphically, equating the function to zero means setting a condition of the function such that the y value is 0, in other words, where the parabola intercepts the x-axis.

The solutions of the quadratic equation allow us to find these two points. If there are no real number solutions, i.e., the solutions are imaginary numbers, the parabola doesn't intersect the x-axis.

The solutions or *roots *of a quadratic equation are given by the equation:

**Example 1: Find the x-axis intercepts of the parabola y = 3x ^{2} + 7x + 2**

**Solution**

- y = ɑx
^{2}+ bx + c

- In our example y = 3x
^{2}+ 7x + 2

- Identify the coefficients and constant c

- So ɑ = 3, b = 7 and c = 2

- The roots of the quadratic equation 3x
^{2}+ 7x + 2 = 0 are at x = (-b ± √(b^{2}- 4ɑc)) / 2ɑ

- Substitute for ɑ, b and c

- The first root is at x = (-7 + √(7
^{2}- 4 x 3 x 2)) / (2 x 3) = -1/3

- The second root is at (-7 - √(7
^{2}- 4 x 3 x 2)) / (2 x 3) = -2

- So the x axis intercepts occur at (-2, 0) and (-1/3, 0)