Updated on December 13, 2016 Here, we will be finding the nth term of a quadratic number sequence. A quadratic number sequence has nth term = an² + bn + c

Example 1

Write down the nth term of this quadratic number sequence.

-3, 8, 23, 42, 65...

Step 1: Confirm the sequence is quadratic. This is done by finding the second difference.

Sequence = -3, 8, 23, 42, 65

1st difference = 11,15,19,23

2nd difference = 4,4,4,4

Step 2: If you divide the second difference by 2, you will get the value of a.

4 ÷ 2 = 2

So the first term of the nth term is 2n²

Step 3: Next, substitute the number 1 to 5 into 2n².

n = 1,2,3,4,5

2n² = 2,8,18,32,50

Step 4: Now, take these values (2n²) from the numbers in the original number sequence and work out the nth term of these numbers that form a linear sequence.

n = 1,2,3,4,5

2n² = 2,8,18,32,50

Differences = -5,0,5,10,15

Now the nth term of these differences (-5,0,5,10,15) is 5n -10.

So b = 5 and c = -10.

Step 5: Write down your final answer in the form an² + bn + c.

2n² + 5n -10

Example 2

Write down the nth term of this quadratic number sequence.

9, 28, 57, 96, 145...

Step 1: Confirm if the sequence is quadratic. This is done by finding the second difference.

Sequence = 9, 28, 57, 96, 145...

1st differences = 19,29,39,49

2nd differences = 10,10,10

Step 2: If you divide the second difference by 2, you will get the value of a.

10 ÷ 2 = 5

So the first term of the nth term is 5n²

Step 3: Next, substitute the number 1 to 5 into 5n².

n = 1,2,3,4,5

5n² = 5,20,45,80,125

Step 4: Now, take these values (5n²) from the numbers in the original number sequence and work out the nth term of these numbers that form a linear sequence.

n = 1,2,3,4,5

5n² = 5,20,45,80,125

Differences = 4,8,12,16,20

Now the nth term of these differences (4,8,12,16,20) is 4n. So b = 4 and c = 0.

Step 5: Write down your final answer in the form an² + bn + c.

5n² + 4n

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Submit a Comment
• hellom8

11 months ago

this is very helpful , cheers

• confusedchild

16 months ago

im still a bit confused how you work out 'c' like how did you get -10 / 0?

• louisearabiana

19 months ago

where does this difference came from, like the 4,8,12,16,20?

• AUTHOR

Mark

2 years ago from England, UK

This would rarely happen, but you can still apply the same method. Just put a decimal before n squared.

• its ya boi

2 years ago

What if the second difference is an odd number?

• Silver49

6 years ago

Very good explanation I will recommend this site to any one who has got problem understanding quadratic sequence

• MKING

6 years ago

its it the same if you get for example 3n+3n+3n+1 like 3 nth terms do u just go and make a third sequence from your second sequence

• cool guy

6 years ago

what do you do if the number only repeats after 4 differences:

1 1 2 7 21

0 1 5 14 1

1 4 9 2

3 5 3

2 4

What is the equation?

• Gervasius Stephanus

6 years ago

Conceptual undertanding is very important for students to comprehend quadratic sequence. Hence, the logic of determining the terms of a given sequence defined by a quadratic formula should be the starting point.

• Dr Gervasius Stephen

6 years ago

The procedure helps far better but understanding of the concept per se in changing the sequence to arithmetic number sequence should be greatly emphasised.

• MathFabPhobiaCured

6 years ago

dat is just dam cul. luving dis site. helpd me a lot.

• shafster

7 years ago

its epic

• sid

7 years ago

brilliant i was having trouble with quadratic sequences and this helped a lot thanks

• Angel

7 years ago

N is number of term.

• Angel

7 years ago

Dats cul

• matthias caruana

8 years ago

In step one there's a mistake in the first difference

it should be 11,15,19,23

• Me.

8 years ago

thanks for this, had trouble understanding for my maths homework

working