Current Transformer  Definition, Principle, Equivalent Circuit, Errors, and Types
Definition
A current transformer is an instrument transformer, used along with measuring or protective devices, in which the secondary current is proportional to the primary current (under normal conditions of operation) and differs from it by an angle that is approximately zero.
Functions
Current transformers perform the following functions:
 Current transformers supply the protective relays with currents of magnitude proportional to those of power circuit but sufficiently reduced in magnitude.
 The measuring devices cannot be directly connected to the high magnitude supplies. Hence current transformers are used to supply those devices with currents of magnitude proportional to those of power.
 A current transformer also isolates the measuring instruments from high voltage circuits.
Current Transformer
Principle
The basic principle of the current transformer is the same as that of the power transformer. Like the power transformer, the current transformer also contains a primary and a secondary winding. Whenever an alternating current flows through the primary winding, alternating magnetic flux is produced, which then induces alternating current in the secondary winding. In the case of current transformers, the load impedance or “burden” is very small. Therefore the current transformer operates under short circuit conditions. Also the current in the secondary winding does not depend on load impedance but instead depends on the current flowing in the primary winding.
The current transformer basically consists of an iron core upon which primary and secondary windings are wound. The primary winding of the transformer is connected in series with the load and carries the actual current flowing to the load, while the secondary winding is connected to a measuring device or a relay. The number of secondary turns is proportional to the current flowing through the primary; i.e., the larger the magnitude of current flowing through the primary, more the number of secondary turns.
The ratio of primary current to the secondary current is known as the current transformation ratio of the CT. Usually the current transformation ratio of the CT is high. Normally the secondary ratings are of the order 5 A, 1 A, 0.1 A, whereas the primary ratings vary from 10 A to 3000 A or more.
The CT handles much less power. Rated burden can be defined as the product of current and voltage at the secondary side of the CT. It is measured in volt ampere (VA).
The secondary of a current transformer should not be disconnected from its rated burden while current is flowing in the primary. As the primary current is independent of the secondary current, the entire primary current acts as a magnetizing current when secondary is opened. This results in deep saturation of the core, which cannot return to normal state and so the CT is no longer usable.
Types: Bar, Wound, and Window
Types
Based on the function performed by the current transformer, it can be classified is follows:
 Measuring current transformers. These current transformers are used along with the measuring devices for the measurement of current, energy, and power.
 Protective current transformers. These current transformers are used along with the protection equipments such as trip coils, relays, etc.
Based on the function construction, it can also be classified as follows:
 Bar Type. This type consists of a bar of suitable size and material forming an integral part of the transformer.
 Wound Type. This type has a primary winding of ore than one full turn wound over the core.
 Window Type. This type has no primary winding. The secondary wind of the CT is placed around the current flowing conductor. The magnetic electric field created by current flowing through the conductor induces current in the secondary winding, which is used for measurement.
Figure 1  Phasor diagram of an ideal CT
Figure 2  Phasor diagram of an actual CT
Errors
The ideal current transformer may be defined as one in which any primary condition is reproduced in the secondary circuit in the exact ratio and phase relationship. The phasor diagram for an ideal current transformer is shown in Figure 1.
For an ideal transformer:
I_{p }T_{p} = I_{s} T_{s}
I_{p} / I_{s} = T_{s} / T_{p}
Therefore the ratio of primary and secondary winding currents equal to the turns ratio. Also the primary and secondary winding currents are exactly 180^{0} in phase.
In an actual transformer, the windings have resistance and reactance and also the transformer has magnetizing and loss component of current to maintain the flux (see Figure 2). Therefore, in an actual transformer the ratio of current is not equal to the turns ratio and also there is a phase difference between the primary current and the secondary currents reflected back on the primary side and consequently we have ratio error and phase angle error.
K_{n} = turns ratio
= number of secondary winding turns / number of primary winding turns,
r_{s}, x_{s} = resistance and reactance respectively of the secondary winding,
r_{p}, x_{p} = resistance and reactance respectively of the primary winding,
E_{p}, E_{s} = primary and secondary induced voltages respectively,
T_{p}, T_{s} = number of primary winding and secondary winding turns respectively,
I_{p}, I_{s} = primary and secondary winding currents respectively,
θ = phase angle of the transformer
Φ_{m} = working flux of the transformer
δ = angle between secondary induced voltage and secondary current,
I_{o } = exciting current,
I_{m} = magnetizing component of exciting current
I_{l} = loss component of exciting current,
α = angle between I_{o} and Φ_{m}
Actual transformation ratio
R = I_{p} / I_{s}
= K_{n} + (I_{l} cos δ + I_{m }sin δ)/ K_{n}I_{s}
Phase angle θ = 180/ π (I_{l} cos δ + I_{m }sin δ)/ K_{n}I_{s}
Ratio error = (K_{n}I_{s}  I_{p})/ I_{p} x 100%
= (K_{n} – R) / R x 100 %
Secondary Current Rating
The value of the rated secondary current is 5A. A secondary current rating of 2A and 1A may also be used in some cases if the number of secondary turns is low and the ratio cannot be adjusted within the required limits by the addition or removal of one turn, if the length of secondary connecting lead is such that the burden due to them at higher secondary current would be excessive.
The disadvantage of making transformers with lower secondary current ratings is that they produce much higher voltage if they are ever accidentally left open circuited. For this reason, it is better to adopt 5 A rating at the secondary.
Turns Compensation
Turns compensation is used in current transformers in order to reduce ratio error. If the phase angle of secondary is zero;
R = K_{n} + I_{l}/ I_{s}
The reduction in the number of secondary turns will reduce the actual transformation ratio b an equal percentage. Usually the best number of secondary turns is 1 or 2 fewer than the number that will make K_{n} equal to the nominal current ratio of the transformer.
Terminology of Current Transformer
Rated transformation ratio. The ratio transformation ratio is defined as the ratio of the rated primary current to the rated secondary current.
Current error (ratio error). The percentage error in the magnitude of the secondary current is defined by the following formula:
Ratio error = (K_{n}I_{s}  I_{p})/ I_{p} x 100%
I_{p}, I_{s} = primary and secondary winding currents respectively,
K_{n} = turns ratio
Accuracy class. Accuracy class tells you how accurate the current transformer is. Accuracy class shall be 0.2, 0.5, 1, 3 or 5. For example, if the accuracy class of a current transformer is 1, then the ratio error will be ±1% at the rated primary value.
Phase displacement. The difference in phase between the primary and the secondary current phasors, the direction of the phasors being chosen such that the angle is zero for a perfect transformer.
Rated secondary current. The value of rated secondary current shall be 5 A. The secondary currents rating of 2 and 1 A may also be used in some case.
Rated burden. The product of current and voltage at the secondary side of the CT is called the rated burden. It is measured in volt ampere (VA).
Table 1  Rated Primary Current
ampere
 ampere
 ampere
 ampere
 ampere


0.5
 10
 100
 1000
 10000

1
 12.5
 125
 1250
 
2.2
 15
 150
 1500
 
5
 20
 200
 2000
 
25
 250
 2500
 
30
 300
 3000
 
40
 400
 4000
 
50
 500
 5000
 
60
 600
 6000
 
75
 750
 7500
 
800

Temperature Rise
The temperature rise of the current transformer's winding when carrying a rated primary current, at rated frequency and with rated burden, should not exceed the approximate values given in Table 2.
Table 2  Limits of Temperature Rise of Windings
Class of Insulation
 Max Temperature Rise (Deg. Celsius)


All classes immersed in oil
 60

All classes immersed in bituminous compound
 50

Y
 45

A
 60

E
 75

B
 85

F
 110

H
 135

Questions & Answers
Comments
Very good lesson
@OSBERT JOEL C
How it can possible CT work in ambient temperature 135 Degree ?
However it fix on busbar directly through it could measure high current.
If CT work in such ambient temp then what is max. Temp of CT should allow during Design stage.
What about selections of CT?
Mr Bonny, When the secondary of CT is open, there will be no opposing secondary ampere turns to the primary ampere turns. This creates very high flux in the core and results in high voltage across the secondary terminals. This is hazardous to insulation and also the operator. The voltage rating of the burden has nothing to do with that. In fact a simple fuse wire across the secondary terminals will suffice in place of a burden to tackle the above phenomenon in case of any maintenance or temporary outage of the instrumentation connected on the secondary side.
when the ct secondary is open circuited there will be high voltage, and when we connect the burden to the secondary does it mean the burden has high voltage rating?which corresponds to the open circuit voltage of ct secondary?
Can you explain simply about ct
nice explanation of c.t.
Oh nice dear
ive just replace a Power Factor Regulator at a switch board.
Ive got to key in the Current Transformer Primary Value.
The range is between 5  10000.
What does it mean by that..
Please advice.
Thanks.
i want to know what happens to a 500.5A, class 5p15 , 30VA CT When 12 KA fault current flows through it?
Secondary total burden along with CT resistance is 1.25ohms.
How is error calculated with Burden ?
Very nice
Thanks sir
To good.....all the information is on the mark.
Bt i suggest you to represent the explanation in point wise method.
Thank you sir
current transformer mathematical equations?
Up to point contents are include.Nice
Thank you for this site
Very good answers,to be showing point wise is good to study.
Thank you for knowdge in this site
thank you sir for this
what's hot temperature Current transfarmar.
Good answer but i suggest important points are write in point wise. Thank you sir
Good answer
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